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132123303230023 = 718874757604289
BaseRepresentation
bin11110000010101001011010…
…100011100011101001000111
3122022210212100011122012222001
4132002221122203203221013
5114304202011111330043
61145000335123050131
736554410423316260
oct3602513243435107
9568725304565861
10132123303230023
113910a1a62537a6
121299a46ab10947
1358952354771a1
14248ab32971967
151041c6c51b74d
hex782a5a8e3a47

132123303230023 has 4 divisors (see below), whose sum is σ = 150998060834320. Its totient is φ = 113248545625728.

The previous prime is 132123303229979. The next prime is 132123303230069. The reversal of 132123303230023 is 320032303321231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132123303230023 is a prime.

It is a super-4 number, since 4×1321233032300234 (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 132123303229973 and 132123303230000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132123303230123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9437378802138 + ... + 9437378802151.

It is an arithmetic number, because the mean of its divisors is an integer number (37749515208580).

Almost surely, 2132123303230023 is an apocalyptic number.

132123303230023 is a deficient number, since it is larger than the sum of its proper divisors (18874757604297).

132123303230023 is an equidigital number, since it uses as much as digits as its factorization.

132123303230023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18874757604296.

The product of its (nonzero) digits is 11664, while the sum is 28.

Adding to 132123303230023 its reverse (320032303321231), we get a palindrome (452155606551254).

The spelling of 132123303230023 in words is "one hundred thirty-two trillion, one hundred twenty-three billion, three hundred three million, two hundred thirty thousand, twenty-three".

Divisors: 1 7 18874757604289 132123303230023