Base | Representation |
---|---|
bin | 11110000010101010000100… |
… | …001010001001101001001001 |
3 | 122022210221010211000102121110 |
4 | 132002222010022021221021 |
5 | 114304204423302304001 |
6 | 1145000532255200533 |
7 | 36554433630140130 |
oct | 3602520412115111 |
9 | 568727124012543 |
10 | 132124001213001 |
11 | 3910a524245736 |
12 | 1299a624816149 |
13 | 5895316c5b475 |
14 | 248ab9b542917 |
15 | 1041cad9413d6 |
hex | 782a84289a49 |
132124001213001 has 32 divisors (see below), whose sum is σ = 213468084910080. Its totient is φ = 70960544430336.
The previous prime is 132124001212993. The next prime is 132124001213027. The reversal of 132124001213001 is 100312100421231.
It is not a de Polignac number, because 132124001213001 - 23 = 132124001212993 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is not an unprimeable number, because it can be changed into a prime (132124001213081) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 254276391 + ... + 254795468.
It is an arithmetic number, because the mean of its divisors is an integer number (6670877653440).
Almost surely, 2132124001213001 is an apocalyptic number.
It is an amenable number.
132124001213001 is a deficient number, since it is larger than the sum of its proper divisors (81344083697079).
132124001213001 is a wasteful number, since it uses less digits than its factorization.
132124001213001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 509072613.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 132124001213001 its reverse (100312100421231), we get a palindrome (232436101634232).
The spelling of 132124001213001 in words is "one hundred thirty-two trillion, one hundred twenty-four billion, one million, two hundred thirteen thousand, one".
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