1321240223041 has 4 divisors (see below), whose sum is σ = 1321254808000. Its totient is φ = 1321225638084.

The previous prime is 1321240222961. The next prime is 1321240223059. The reversal of 1321240223041 is 1403220421231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1321240223041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1321240222997 and 1321240223015.

It is not an unprimeable number, because it can be changed into a prime (1321240223741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7155741 + ... + 7338058.

It is an arithmetic number, because the mean of its divisors is an integer number (330313702000).

Almost surely, 2^{1321240223041} is an apocalyptic number.

It is an amenable number.

1321240223041 is a deficient number, since it is larger than the sum of its proper divisors (14584959).

1321240223041 is an equidigital number, since it uses as much as digits as its factorization.

1321240223041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14584958.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1321240223041 its reverse (1403220421231), we get a palindrome (2724460644272).

The spelling of 1321240223041 in words is "one trillion, three hundred twenty-one billion, two hundred forty million, two hundred twenty-three thousand, forty-one".