132124104043331 has 4 divisors (see below), whose sum is σ = 132124685907600. Its totient is φ = 132123522179064.

The previous prime is 132124104043301. The next prime is 132124104043363. The reversal of 132124104043331 is 133340401421231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132124104043331 - 2²⁶ = 132124036934467 is a prime.

It is a super-3 number, since 3×132124104043331³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132124104043301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 290591396 + ... + 291045713.

It is an arithmetic number, because the mean of its divisors is an integer number (33031171476900).

Almost surely, 2^{132124104043331} is an apocalyptic number.

132124104043331 is a deficient number, since it is larger than the sum of its proper divisors (581864269).

132124104043331 is an equidigital number, since it uses as much as digits as its factorization.

132124104043331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 581864268.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 132124104043331 its reverse (133340401421231), we get a palindrome (265464505464562).

The spelling of 132124104043331 in words is "one hundred thirty-two trillion, one hundred twenty-four billion, one hundred four million, forty-three thousand, three hundred thirty-one".