Base | Representation |
---|---|
bin | 11110000010101010010010… |
… | …100110000100010110111011 |
3 | 122022210221202200202102201222 |
4 | 132002222102212010112323 |
5 | 114304210422303144121 |
6 | 1145001012310302255 |
7 | 36554442630612635 |
oct | 3602522246042673 |
9 | 568727680672658 |
10 | 132124243412411 |
11 | 3910a638a30738 |
12 | 1299a69195798b |
13 | 589535519c423 |
14 | 248abc178ba55 |
15 | 1041cc4d340ab |
hex | 782a929845bb |
132124243412411 has 4 divisors (see below), whose sum is σ = 132124308723000. Its totient is φ = 132124178101824.
The previous prime is 132124243412393. The next prime is 132124243412431. The reversal of 132124243412411 is 114214342421231.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132124243412411 - 210 = 132124243411387 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132124243412431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29520461 + ... + 33700238.
It is an arithmetic number, because the mean of its divisors is an integer number (33031077180750).
Almost surely, 2132124243412411 is an apocalyptic number.
132124243412411 is a deficient number, since it is larger than the sum of its proper divisors (65310589).
132124243412411 is an equidigital number, since it uses as much as digits as its factorization.
132124243412411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65310588.
The product of its digits is 36864, while the sum is 35.
Adding to 132124243412411 its reverse (114214342421231), we get a palindrome (246338585833642).
The spelling of 132124243412411 in words is "one hundred thirty-two trillion, one hundred twenty-four billion, two hundred forty-three million, four hundred twelve thousand, four hundred eleven".
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