Base | Representation |
---|---|
bin | 11110000010101010010110… |
… | …001001111011010001010111 |
3 | 122022210221220212011010002220 |
4 | 132002222112021323101113 |
5 | 114304211033101102043 |
6 | 1145001022242433423 |
7 | 36554444254411401 |
oct | 3602522611732127 |
9 | 568727825133086 |
10 | 132124303144023 |
11 | 3910a669718a03 |
12 | 1299a6a9962873 |
13 | 5895364684188 |
14 | 248abc9699b71 |
15 | 1041cca1d2483 |
hex | 782a9627b457 |
132124303144023 has 8 divisors (see below), whose sum is σ = 176165997407088. Its totient is φ = 88082738821824.
The previous prime is 132124303143947. The next prime is 132124303144033. The reversal of 132124303144023 is 320441303421231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132124303144023 - 213 = 132124303135831 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132124303144033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30087390 + ... + 34197947.
It is an arithmetic number, because the mean of its divisors is an integer number (22020749675886).
Almost surely, 2132124303144023 is an apocalyptic number.
132124303144023 is a deficient number, since it is larger than the sum of its proper divisors (44041694263065).
132124303144023 is an equidigital number, since it uses as much as digits as its factorization.
132124303144023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64970433.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 132124303144023 its reverse (320441303421231), we get a palindrome (452565606565254).
The spelling of 132124303144023 in words is "one hundred thirty-two trillion, one hundred twenty-four billion, three hundred three million, one hundred forty-four thousand, twenty-three".
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