Search a number
-
+
132125340551335 = 5246831070577649
BaseRepresentation
bin11110000010101011010011…
…111111010100100010100111
3122022211001121011012212101221
4132002223103333110202213
5114304220144140120320
61145001313222001211
736554512052261455
oct3602532377244247
9568731534185357
10132125340551335
113911005127141a
121299a939276207
13589549b58aa61
14248ac873839d5
151041d3b3023aa
hex782ad3fd48a7

132125340551335 has 8 divisors (see below), whose sum is σ = 158556832275600. Its totient is φ = 105695990031744.

The previous prime is 132125340551311. The next prime is 132125340551431. The reversal of 132125340551335 is 533155043521231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132125340551335 - 29 = 132125340550823 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132125340551291 and 132125340551300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 535165410 + ... + 535412239.

It is an arithmetic number, because the mean of its divisors is an integer number (19819604034450).

Almost surely, 2132125340551335 is an apocalyptic number.

132125340551335 is a deficient number, since it is larger than the sum of its proper divisors (26431491724265).

132125340551335 is a wasteful number, since it uses less digits than its factorization.

132125340551335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1070602337.

The product of its (nonzero) digits is 810000, while the sum is 43.

The spelling of 132125340551335 in words is "one hundred thirty-two trillion, one hundred twenty-five billion, three hundred forty million, five hundred fifty-one thousand, three hundred thirty-five".

Divisors: 1 5 24683 123415 1070577649 5352888245 26425068110267 132125340551335