Base | Representation |
---|---|
bin | 11110000010101011010011… |
… | …111111010100100010100111 |
3 | 122022211001121011012212101221 |
4 | 132002223103333110202213 |
5 | 114304220144140120320 |
6 | 1145001313222001211 |
7 | 36554512052261455 |
oct | 3602532377244247 |
9 | 568731534185357 |
10 | 132125340551335 |
11 | 3911005127141a |
12 | 1299a939276207 |
13 | 589549b58aa61 |
14 | 248ac873839d5 |
15 | 1041d3b3023aa |
hex | 782ad3fd48a7 |
132125340551335 has 8 divisors (see below), whose sum is σ = 158556832275600. Its totient is φ = 105695990031744.
The previous prime is 132125340551311. The next prime is 132125340551431. The reversal of 132125340551335 is 533155043521231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132125340551335 - 29 = 132125340550823 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132125340551291 and 132125340551300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 535165410 + ... + 535412239.
It is an arithmetic number, because the mean of its divisors is an integer number (19819604034450).
Almost surely, 2132125340551335 is an apocalyptic number.
132125340551335 is a deficient number, since it is larger than the sum of its proper divisors (26431491724265).
132125340551335 is a wasteful number, since it uses less digits than its factorization.
132125340551335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1070602337.
The product of its (nonzero) digits is 810000, while the sum is 43.
The spelling of 132125340551335 in words is "one hundred thirty-two trillion, one hundred twenty-five billion, three hundred forty million, five hundred fifty-one thousand, three hundred thirty-five".
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