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13213000203202 = 26606500101601
BaseRepresentation
bin1100000001000110010000…
…1011101111101111000010
31201210011001200221221222101
43000101210023233233002
53212440211023000302
644033545110101014
72532415314430432
oct300214413575702
951704050857871
1013213000203202
114234669174a88
12159492704a76a
1374ac9941a907
143397268c62c2
1517da7909d287
hexc04642efbc2

13213000203202 has 4 divisors (see below), whose sum is σ = 19819500304806. Its totient is φ = 6606500101600.

The previous prime is 13213000203133. The next prime is 13213000203203. The reversal of 13213000203202 is 20230200031231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11531260684441 + 1681739518761 = 3395771^2 + 1296819^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 13213000203202.

It is not an unprimeable number, because it can be changed into a prime (13213000203203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3303250050799 + ... + 3303250050802.

Almost surely, 213213000203202 is an apocalyptic number.

13213000203202 is a deficient number, since it is larger than the sum of its proper divisors (6606500101604).

13213000203202 is an equidigital number, since it uses as much as digits as its factorization.

13213000203202 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6606500101603.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 13213000203202 its reverse (20230200031231), we get a palindrome (33443200234433).

The spelling of 13213000203202 in words is "thirteen trillion, two hundred thirteen billion, two hundred three thousand, two hundred two".

Divisors: 1 2 6606500101601 13213000203202