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132130501441 = 406273252283
BaseRepresentation
bin111101100001110010…
…1110111001101000001
3110122001101211221011121
41323003211313031001
54131100402021231
6140411103112241
712355213505551
oct1730345671501
9418041757147
10132130501441
1151044250424
12217362a2681
13c5c93b1983
146576415161
153684e03311
hex1ec3977341

132130501441 has 4 divisors (see below), whose sum is σ = 132133794352. Its totient is φ = 132127208532.

The previous prime is 132130501439. The next prime is 132130501483. The reversal of 132130501441 is 144105031231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132130501441 - 21 = 132130501439 is a prime.

It is a super-2 number, since 2×1321305014412 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132130501411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1585515 + ... + 1666768.

It is an arithmetic number, because the mean of its divisors is an integer number (33033448588).

Almost surely, 2132130501441 is an apocalyptic number.

It is an amenable number.

132130501441 is a deficient number, since it is larger than the sum of its proper divisors (3292911).

132130501441 is an equidigital number, since it uses as much as digits as its factorization.

132130501441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3292910.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 132130501441 its reverse (144105031231), we get a palindrome (276235532672).

The spelling of 132130501441 in words is "one hundred thirty-two billion, one hundred thirty million, five hundred one thousand, four hundred forty-one".

Divisors: 1 40627 3252283 132130501441