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132131011301 = 294556241769
BaseRepresentation
bin111101100001110011…
…1110011101011100101
3110122001102210211120022
41323003213303223211
54131101014330201
6140411122044525
712355221031202
oct1730347635345
9418042724508
10132131011301
11510445694a3
12217364a9745
13c5c952ca73
146576508ca9
153684ea441b
hex1ec39f3ae5

132131011301 has 4 divisors (see below), whose sum is σ = 136687253100. Its totient is φ = 127574769504.

The previous prime is 132131011279. The next prime is 132131011321. The reversal of 132131011301 is 103110131231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 103110131231 = 227454229653.

It can be written as a sum of positive squares in 2 ways, for example, as 42160408900 + 89970602401 = 205330^2 + 299951^2 .

It is a cyclic number.

It is not a de Polignac number, because 132131011301 - 230 = 131057269477 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 132131011301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132131011321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2278120856 + ... + 2278120913.

It is an arithmetic number, because the mean of its divisors is an integer number (34171813275).

Almost surely, 2132131011301 is an apocalyptic number.

It is an amenable number.

132131011301 is a deficient number, since it is larger than the sum of its proper divisors (4556241799).

132131011301 is an equidigital number, since it uses as much as digits as its factorization.

132131011301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4556241798.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 132131011301 its reverse (103110131231), we get a palindrome (235241142532).

The spelling of 132131011301 in words is "one hundred thirty-two billion, one hundred thirty-one million, eleven thousand, three hundred one".

Divisors: 1 29 4556241769 132131011301