Base | Representation |
---|---|
bin | 1100000001000110101110… |
… | …0000010000011001110011 |
3 | 1201210011101021001201111121 |
4 | 3000101223200100121303 |
5 | 3212440433443123103 |
6 | 44034005214323111 |
7 | 2532421335364165 |
oct | 300215340203163 |
9 | 51704337051447 |
10 | 13213123020403 |
11 | 42347215303a9 |
12 | 15949601b9497 |
13 | 74acb89bcc07 |
14 | 339738d36935 |
15 | 17da84c5d6bd |
hex | c046b810673 |
13213123020403 has 16 divisors (see below), whose sum is σ = 13460609916000. Its totient is φ = 12967507897344.
The previous prime is 13213123020397. The next prime is 13213123020481. The reversal of 13213123020403 is 30402032131231.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13213123020403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13213123026403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25237375 + ... + 25755607.
It is an arithmetic number, because the mean of its divisors is an integer number (841288119750).
Almost surely, 213213123020403 is an apocalyptic number.
13213123020403 is a deficient number, since it is larger than the sum of its proper divisors (247486895597).
13213123020403 is a wasteful number, since it uses less digits than its factorization.
13213123020403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 520038.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 13213123020403 its reverse (30402032131231), we get a palindrome (43615155151634).
The spelling of 13213123020403 in words is "thirteen trillion, two hundred thirteen billion, one hundred twenty-three million, twenty thousand, four hundred three".
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