Base | Representation |
---|---|
bin | 1100000001000111001101… |
… | …0111110100000111001111 |
3 | 1201210011201110110020220120 |
4 | 3000101303113310013033 |
5 | 3212441221241300403 |
6 | 44034030251520023 |
7 | 2532424530404430 |
oct | 300216327640717 |
9 | 51704643406816 |
10 | 13213255025103 |
11 | 4234789aa14a1 |
12 | 1594998459013 |
13 | 74b00a15acc3 |
14 | 33974c699487 |
15 | 17da91635e53 |
hex | c04735f41cf |
13213255025103 has 16 divisors (see below), whose sum is σ = 20134564143360. Its totient is φ = 7550401332096.
The previous prime is 13213255025101. The next prime is 13213255025107. The reversal of 13213255025103 is 30152055231231.
13213255025103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13213255025103 - 21 = 13213255025101 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13213255025101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4820788 + ... + 7047446.
It is an arithmetic number, because the mean of its divisors is an integer number (1258410258960).
Almost surely, 213213255025103 is an apocalyptic number.
13213255025103 is a deficient number, since it is larger than the sum of its proper divisors (6921309118257).
13213255025103 is a wasteful number, since it uses less digits than its factorization.
13213255025103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2509246.
The product of its (nonzero) digits is 27000, while the sum is 33.
The spelling of 13213255025103 in words is "thirteen trillion, two hundred thirteen billion, two hundred fifty-five million, twenty-five thousand, one hundred three".
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