Search a number
-
+
1321340001455 = 5594479118649
BaseRepresentation
bin10011001110100110000…
…000000101110010101111
311200022121110022211220102
4103032212000011302233
5133122101020021310
62451003141541315
7164315015461145
oct23164600056257
94608543284812
101321340001455
1146a416a90131
1219410211483b
13977a92a4436
1447d4b805595
15245876338a5
hex133a6005caf

1321340001455 has 8 divisors (see below), whose sum is σ = 1612482714000. Its totient is φ = 1039155526336.

The previous prime is 1321340001431. The next prime is 1321340001503. The reversal of 1321340001455 is 5541000431231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1321340001455 - 218 = 1321339739311 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2239559030 + ... + 2239559619.

It is an arithmetic number, because the mean of its divisors is an integer number (201560339250).

Almost surely, 21321340001455 is an apocalyptic number.

1321340001455 is a deficient number, since it is larger than the sum of its proper divisors (291142712545).

1321340001455 is an equidigital number, since it uses as much as digits as its factorization.

1321340001455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4479118713.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 1321340001455 its reverse (5541000431231), we get a palindrome (6862340432686).

The spelling of 1321340001455 in words is "one trillion, three hundred twenty-one billion, three hundred forty million, one thousand, four hundred fifty-five".

Divisors: 1 5 59 295 4479118649 22395593245 264268000291 1321340001455