Base | Representation |
---|---|
bin | 11000100111001100… |
… | …00111001111110011 |
3 | 1021002212211111002021 |
4 | 30103212013033303 |
5 | 204030144111042 |
6 | 10023102332311 |
7 | 645306154342 |
oct | 142346071763 |
9 | 37085744067 |
10 | 13213660147 |
11 | 5670848496 |
12 | 268928a097 |
13 | 132772c81c |
14 | 8d4ca5b59 |
15 | 5250a8867 |
hex | 3139873f3 |
13213660147 has 4 divisors (see below), whose sum is σ = 13221466720. Its totient is φ = 13205853576.
The previous prime is 13213660127. The next prime is 13213660153. The reversal of 13213660147 is 74106631231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74106631231 = 1867 ⋅39692893.
It is a cyclic number.
It is not a de Polignac number, because 13213660147 - 215 = 13213627379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13213660127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3900747 + ... + 3904132.
It is an arithmetic number, because the mean of its divisors is an integer number (3305366680).
Almost surely, 213213660147 is an apocalyptic number.
13213660147 is a deficient number, since it is larger than the sum of its proper divisors (7806573).
13213660147 is an equidigital number, since it uses as much as digits as its factorization.
13213660147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7806572.
The product of its (nonzero) digits is 18144, while the sum is 34.
The spelling of 13213660147 in words is "thirteen billion, two hundred thirteen million, six hundred sixty thousand, one hundred forty-seven".
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