Base | Representation |
---|---|
bin | 1100000001001001000001… |
… | …0010100111001000100011 |
3 | 1201210012222021101201102002 |
4 | 3000102100102213020203 |
5 | 3212443214442403413 |
6 | 44034150342514215 |
7 | 2532442541336054 |
oct | 300222022471043 |
9 | 51705867351362 |
10 | 13213740200483 |
11 | 4234a08952989 |
12 | 1594ab2a3596b |
13 | 74b086822524 |
14 | 339796cb272b |
15 | 17dabe021958 |
hex | c04904a7223 |
13213740200483 has 4 divisors (see below), whose sum is σ = 13317785399040. Its totient is φ = 13109695001928.
The previous prime is 13213740200459. The next prime is 13213740200489. The reversal of 13213740200483 is 38400204731231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13213740200483 - 224 = 13213723423267 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13213740200489) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52022599088 + ... + 52022599341.
It is an arithmetic number, because the mean of its divisors is an integer number (3329446349760).
Almost surely, 213213740200483 is an apocalyptic number.
13213740200483 is a deficient number, since it is larger than the sum of its proper divisors (104045198557).
13213740200483 is a wasteful number, since it uses less digits than its factorization.
13213740200483 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 104045198556.
The product of its (nonzero) digits is 96768, while the sum is 38.
The spelling of 13213740200483 in words is "thirteen trillion, two hundred thirteen billion, seven hundred forty million, two hundred thousand, four hundred eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •