Base | Representation |
---|---|
bin | 1100000001001001111111… |
… | …1110010011001100101011 |
3 | 1201210020122121111010201222 |
4 | 3000102133332103030223 |
5 | 3212444234321431103 |
6 | 44034232422132255 |
7 | 2532452214625226 |
oct | 300223776231453 |
9 | 51706577433658 |
10 | 13214003311403 |
11 | 4235033421024 |
12 | 1594b66b8108b |
13 | 74b0c91a576b |
14 | 3397bdc025bd |
15 | 17dad7195638 |
hex | c049ff9332b |
13214003311403 has 4 divisors (see below), whose sum is σ = 13214022354288. Its totient is φ = 13213984268520.
The previous prime is 13214003311381. The next prime is 13214003311427. The reversal of 13214003311403 is 30411330041231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13214003311403 - 230 = 13212929569579 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13214003311493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8439608 + ... + 9882053.
It is an arithmetic number, because the mean of its divisors is an integer number (3303505588572).
Almost surely, 213214003311403 is an apocalyptic number.
13214003311403 is a deficient number, since it is larger than the sum of its proper divisors (19042885).
13214003311403 is an equidigital number, since it uses as much as digits as its factorization.
13214003311403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19042884.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 13214003311403 its reverse (30411330041231), we get a palindrome (43625333352634).
The spelling of 13214003311403 in words is "thirteen trillion, two hundred fourteen billion, three million, three hundred eleven thousand, four hundred three".
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