Base | Representation |
---|---|
bin | 1100000001001001111111… |
… | …1110010011001101000011 |
3 | 1201210020122121111010202212 |
4 | 3000102133332103031003 |
5 | 3212444234321431202 |
6 | 44034232422132335 |
7 | 2532452214625262 |
oct | 300223776231503 |
9 | 51706577433685 |
10 | 13214003311427 |
11 | 4235033421046 |
12 | 1594b66b810ab |
13 | 74b0c91a5789 |
14 | 3397bdc025d9 |
15 | 17dad7195652 |
hex | c049ff93343 |
13214003311427 has 2 divisors, whose sum is σ = 13214003311428. Its totient is φ = 13214003311426.
The previous prime is 13214003311381. The next prime is 13214003311471. The reversal of 13214003311427 is 72411330041231.
13214003311427 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13214003311427 - 230 = 13212929569603 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13214003311393 and 13214003311402.
It is not a weakly prime, because it can be changed into another prime (13214003314427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607001655713 + 6607001655714.
It is an arithmetic number, because the mean of its divisors is an integer number (6607001655714).
Almost surely, 213214003311427 is an apocalyptic number.
13214003311427 is a deficient number, since it is larger than the sum of its proper divisors (1).
13214003311427 is an equidigital number, since it uses as much as digits as its factorization.
13214003311427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 13214003311427 its reverse (72411330041231), we get a palindrome (85625333352658).
The spelling of 13214003311427 in words is "thirteen trillion, two hundred fourteen billion, three million, three hundred eleven thousand, four hundred twenty-seven".
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