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132140211103 = 283466926541
BaseRepresentation
bin111101100010000101…
…0111001101110011111
3110122002002010020022201
41323010022321232133
54131110343223403
6140412051152331
712355362155605
oct1730412715637
9418062106281
10132140211103
115104978243a
12217395a56a7
13c5cb401334
146577821875
153685bc021d
hex1ec42b9b9f

132140211103 has 4 divisors (see below), whose sum is σ = 132607137928. Its totient is φ = 131673284280.

The previous prime is 132140211053. The next prime is 132140211163. The reversal of 132140211103 is 301112041231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132140211103 - 213 = 132140202911 is a prime.

It is a super-2 number, since 2×1321402111032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132140211163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233462988 + ... + 233463553.

It is an arithmetic number, because the mean of its divisors is an integer number (33151784482).

Almost surely, 2132140211103 is an apocalyptic number.

132140211103 is a deficient number, since it is larger than the sum of its proper divisors (466926825).

132140211103 is an equidigital number, since it uses as much as digits as its factorization.

132140211103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 466926824.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 132140211103 its reverse (301112041231), we get a palindrome (433252252334).

The spelling of 132140211103 in words is "one hundred thirty-two billion, one hundred forty million, two hundred eleven thousand, one hundred three".

Divisors: 1 283 466926541 132140211103