1321404041231 has 4 divisors (see below), whose sum is σ = 1321469643000. Its totient is φ = 1321338439464.

The previous prime is 1321404041161. The next prime is 1321404041233.

1321404041231 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1321404041231 - 2¹⁰ = 1321404040207 is a prime.

It is a super-2 number, since 2×1321404041231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1321404041231.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1321404041233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32770661 + ... + 32810958.

It is an arithmetic number, because the mean of its divisors is an integer number (330367410750).

Almost surely, 2^{1321404041231} is an apocalyptic number.

1321404041231 is a deficient number, since it is larger than the sum of its proper divisors (65601769).

1321404041231 is an equidigital number, since it uses as much as digits as its factorization.

1321404041231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65601768.

The product of its (nonzero) digits is 2304, while the sum is 26.

The spelling of 1321404041231 in words is "one trillion, three hundred twenty-one billion, four hundred four million, forty-one thousand, two hundred thirty-one".