13214041243 has 4 divisors (see below), whose sum is σ = 14230505968. Its totient is φ = 12197576520.

The previous prime is 13214041241. The next prime is 13214041277. The reversal of 13214041243 is 34214041231.

13214041243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13214041243 - 2¹ = 13214041241 is a prime.

It is a super-2 number, since 2×13214041243² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13214041241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 508232343 + ... + 508232368.

It is an arithmetic number, because the mean of its divisors is an integer number (3557626492).

Almost surely, 2^13214041243 is an apocalyptic number.

13214041243 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

13214041243 is a deficient number, since it is larger than the sum of its proper divisors (1016464725).

13214041243 is a wasteful number, since it uses less digits than its factorization.

13214041243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1016464724.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 13214041243 its reverse (34214041231), we get a palindrome (47428082474).

The spelling of 13214041243 in words is "thirteen billion, two hundred fourteen million, forty-one thousand, two hundred forty-three".