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13214131233 = 34404710411
BaseRepresentation
bin11000100111001111…
…11010010000100001
31021002220201102021220
430103213322100201
5204030304144413
610023120405253
7645313155642
oct142347722041
937086642256
1013214131233
11567103a416
122689476829
131327866084
148d4d896c9
1552514d223
hex3139fa421

13214131233 has 4 divisors (see below), whose sum is σ = 17618841648. Its totient is φ = 8809420820.

The previous prime is 13214131201. The next prime is 13214131241. The reversal of 13214131233 is 33213141231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13214131233 - 25 = 13214131201 is a prime.

It is a super-2 number, since 2×132141312332 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13214131033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2202355203 + ... + 2202355208.

It is an arithmetic number, because the mean of its divisors is an integer number (4404710412).

Almost surely, 213214131233 is an apocalyptic number.

It is an amenable number.

13214131233 is a deficient number, since it is larger than the sum of its proper divisors (4404710415).

13214131233 is an equidigital number, since it uses as much as digits as its factorization.

13214131233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4404710414.

The product of its digits is 1296, while the sum is 24.

Adding to 13214131233 its reverse (33213141231), we get a palindrome (46427272464).

The spelling of 13214131233 in words is "thirteen billion, two hundred fourteen million, one hundred thirty-one thousand, two hundred thirty-three".

Divisors: 1 3 4404710411 13214131233