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132141412220204 = 2233035353055051
BaseRepresentation
bin11110000010111010010001…
…111011110111110100101100
3122022212121002012220020102002
4132002322101323313310230
5114310001103012021304
61145012532101351432
736555621244226102
oct3602722173676454
9568777065806362
10132141412220204
1139116949308092
12129a1a83708578
135896b601482aa
14248b96da4dc72
15104247c25331e
hex782e91ef7d2c

132141412220204 has 6 divisors (see below), whose sum is σ = 231247471385364. Its totient is φ = 66070706110100.

The previous prime is 132141412220137. The next prime is 132141412220221. The reversal of 132141412220204 is 402022214141231.

It is a super-2 number, since 2×1321414122202042 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16517676527522 + ... + 16517676527529.

It is an arithmetic number, because the mean of its divisors is an integer number (38541245230894).

Almost surely, 2132141412220204 is an apocalyptic number.

It is an amenable number.

132141412220204 is a deficient number, since it is larger than the sum of its proper divisors (99106059165160).

132141412220204 is a wasteful number, since it uses less digits than its factorization.

132141412220204 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33035353055055 (or 33035353055053 counting only the distinct ones).

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 132141412220204 its reverse (402022214141231), we get a palindrome (534163626361435).

The spelling of 132141412220204 in words is "one hundred thirty-two trillion, one hundred forty-one billion, four hundred twelve million, two hundred twenty thousand, two hundred four".

Divisors: 1 2 4 33035353055051 66070706110102 132141412220204