Base | Representation |
---|---|
bin | 11110000010111100010000… |
… | …111001111110111100101111 |
3 | 122022212210120200021012000001 |
4 | 132002330100321332330233 |
5 | 114310014433330302120 |
6 | 1145013523315245131 |
7 | 36556025111561545 |
oct | 3602742071767457 |
9 | 568783520235001 |
10 | 132143542431535 |
11 | 39117841800418 |
12 | 129a2378ba97a7 |
13 | 589710c58337b |
14 | 248bad2921d95 |
15 | 1042554286e0a |
hex | 782f10e7ef2f |
132143542431535 has 4 divisors (see below), whose sum is σ = 158572250917848. Its totient is φ = 105714833945224.
The previous prime is 132143542431533. The next prime is 132143542431559. The reversal of 132143542431535 is 535134245341231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132143542431535 - 21 = 132143542431533 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132143542431533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13214354243149 + ... + 13214354243158.
It is an arithmetic number, because the mean of its divisors is an integer number (39643062729462).
Almost surely, 2132143542431535 is an apocalyptic number.
132143542431535 is a deficient number, since it is larger than the sum of its proper divisors (26428708486313).
132143542431535 is an equidigital number, since it uses as much as digits as its factorization.
132143542431535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26428708486312.
The product of its digits is 2592000, while the sum is 46.
Adding to 132143542431535 its reverse (535134245341231), we get a palindrome (667277787772766).
The spelling of 132143542431535 in words is "one hundred thirty-two trillion, one hundred forty-three billion, five hundred forty-two million, four hundred thirty-one thousand, five hundred thirty-five".
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