Base | Representation |
---|---|
bin | 11110000010111100010110… |
… | …110100010010000110011010 |
3 | 122022212210211120212111010100 |
4 | 132002330112310102012122 |
5 | 114310020134222203120 |
6 | 1145013541221000230 |
7 | 36556030424522616 |
oct | 3602742664220632 |
9 | 568783746774110 |
10 | 132143641600410 |
11 | 39117892784470 |
12 | 129a23a6253076 |
13 | 5897126c9578b |
14 | 248bb01b78346 |
15 | 104255cd25490 |
hex | 782f16d1219a |
132143641600410 has 384 divisors, whose sum is σ = 386850836736000. Its totient is φ = 31022424921600.
The previous prime is 132143641600379. The next prime is 132143641600463. The reversal of 132143641600410 is 14006146341231.
132143641600410 is a `hidden beast` number, since 1 + 3 + 2 + 1 + 4 + 3 + 6 + 4 + 1 + 600 + 41 + 0 = 666.
It is a super-2 number, since 2×1321436416004102 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 5221198836 + ... + 5221224144.
It is an arithmetic number, because the mean of its divisors is an integer number (1007424054000).
Almost surely, 2132143641600410 is an apocalyptic number.
132143641600410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 132143641600410, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (193425418368000).
132143641600410 is an abundant number, since it is smaller than the sum of its proper divisors (254707195135590).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132143641600410 is a wasteful number, since it uses less digits than its factorization.
132143641600410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26722 (or 26719 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 36.
Adding to 132143641600410 its reverse (14006146341231), we get a palindrome (146149787941641).
The spelling of 132143641600410 in words is "one hundred thirty-two trillion, one hundred forty-three billion, six hundred forty-one million, six hundred thousand, four hundred ten".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •