Base | Representation |
---|---|
bin | 11110000010111100110011… |
… | …011010110001001011110111 |
3 | 122022212212002000210102201212 |
4 | 132002330303122301023313 |
5 | 114310022130042420010 |
6 | 1145014101001512035 |
7 | 36556045342266644 |
oct | 3602746332611367 |
9 | 568785060712655 |
10 | 132144121451255 |
11 | 39118009629511 |
12 | 129a24baaa261b |
13 | 58971a25145a4 |
14 | 248bb497a6dcb |
15 | 104258a00d505 |
hex | 782f336b12f7 |
132144121451255 has 8 divisors (see below), whose sum is σ = 159133274173392. Its totient is φ = 105341744873088.
The previous prime is 132144121451213. The next prime is 132144121451269. The reversal of 132144121451255 is 552154121441231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132144121451255 - 212 = 132144121447159 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46694034434 + ... + 46694037263.
It is an arithmetic number, because the mean of its divisors is an integer number (19891659271674).
Almost surely, 2132144121451255 is an apocalyptic number.
132144121451255 is a deficient number, since it is larger than the sum of its proper divisors (26989152722137).
132144121451255 is an equidigital number, since it uses as much as digits as its factorization.
132144121451255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 93388071985.
The product of its digits is 192000, while the sum is 41.
Adding to 132144121451255 its reverse (552154121441231), we get a palindrome (684298242892486).
The spelling of 132144121451255 in words is "one hundred thirty-two trillion, one hundred forty-four billion, one hundred twenty-one million, four hundred fifty-one thousand, two hundred fifty-five".
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