Base | Representation |
---|---|
bin | 10011001110101100000… |
… | …110110101100001001101 |
3 | 11200022212121001220201002 |
4 | 103032230012311201031 |
5 | 133122303230324401 |
6 | 2451021241230045 |
7 | 164320401231530 |
oct | 23165406654115 |
9 | 4608777056632 |
10 | 1321442433101 |
11 | 46a46989258a |
12 | 194130492325 |
13 | 977c458998b |
14 | 47d5b26aa17 |
15 | 24591618a6b |
hex | 133ac1b584d |
1321442433101 has 4 divisors (see below), whose sum is σ = 1510219923552. Its totient is φ = 1132664942652.
The previous prime is 1321442433053. The next prime is 1321442433119. The reversal of 1321442433101 is 1013342441231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1321442433101 - 26 = 1321442433037 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1321442433301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94388745215 + ... + 94388745228.
It is an arithmetic number, because the mean of its divisors is an integer number (377554980888).
Almost surely, 21321442433101 is an apocalyptic number.
It is an amenable number.
1321442433101 is a deficient number, since it is larger than the sum of its proper divisors (188777490451).
1321442433101 is an equidigital number, since it uses as much as digits as its factorization.
1321442433101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 188777490450.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1321442433101 its reverse (1013342441231), we get a palindrome (2334784874332).
The spelling of 1321442433101 in words is "one trillion, three hundred twenty-one billion, four hundred forty-two million, four hundred thirty-three thousand, one hundred one".
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