Base | Representation |
---|---|
bin | 1100000001001011101011… |
… | …1011000010011101001111 |
3 | 1201210021211010020201021011 |
4 | 3000102322323002131033 |
5 | 3213001201043104411 |
6 | 44034345332550051 |
7 | 2532466344645052 |
oct | 300227273023517 |
9 | 51707733221234 |
10 | 13214455441231 |
11 | 4235245661940 |
12 | 1595072482327 |
13 | 74b16ba699c5 |
14 | 339823c96a99 |
15 | 17db11c04c21 |
hex | c04baec274f |
13214455441231 has 4 divisors (see below), whose sum is σ = 14415769572264. Its totient is φ = 12013141310200.
The previous prime is 13214455441211. The next prime is 13214455441247.
13214455441231 is nontrivially palindromic in base 10.
13214455441231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13214455441231 - 211 = 13214455439183 is a prime.
It is a super-2 number, since 2×132144554412312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13214455441211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 600657065500 + ... + 600657065521.
It is an arithmetic number, because the mean of its divisors is an integer number (3603942393066).
Almost surely, 213214455441231 is an apocalyptic number.
13214455441231 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13214455441231 is a deficient number, since it is larger than the sum of its proper divisors (1201314131033).
13214455441231 is a wasteful number, since it uses less digits than its factorization.
13214455441231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1201314131032.
The product of its digits is 230400, while the sum is 40.
It can be divided in two parts, 1321445 and 5441231, that added together give a palindrome (6762676).
The spelling of 13214455441231 in words is "thirteen trillion, two hundred fourteen billion, four hundred fifty-five million, four hundred forty-one thousand, two hundred thirty-one".
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