Base | Representation |
---|---|
bin | 11110000011000011100000… |
… | …000100100110010001010011 |
3 | 122022220112122020002021020002 |
4 | 132003003200010212101103 |
5 | 114310131342121040133 |
6 | 1145021250343040215 |
7 | 36556421506064666 |
oct | 3603034004462123 |
9 | 568815566067202 |
10 | 132151313065043 |
11 | 3912006a058388 |
12 | 129a398744006b |
13 | 5897a7a42966c |
14 | 248c22c9616dd |
15 | 104285b576ce8 |
hex | 7830e0126453 |
132151313065043 has 4 divisors (see below), whose sum is σ = 132158224402248. Its totient is φ = 132144401727840.
The previous prime is 132151313064959. The next prime is 132151313065063. The reversal of 132151313065043 is 340560313151231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132151313065043 - 214 = 132151313048659 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132151313064988 and 132151313065006.
It is not an unprimeable number, because it can be changed into a prime (132151313065063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3455639921 + ... + 3455678162.
It is an arithmetic number, because the mean of its divisors is an integer number (33039556100562).
Almost surely, 2132151313065043 is an apocalyptic number.
132151313065043 is a deficient number, since it is larger than the sum of its proper divisors (6911337205).
132151313065043 is an equidigital number, since it uses as much as digits as its factorization.
132151313065043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6911337204.
The product of its (nonzero) digits is 97200, while the sum is 38.
The spelling of 132151313065043 in words is "one hundred thirty-two trillion, one hundred fifty-one billion, three hundred thirteen million, sixty-five thousand, forty-three".
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