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13215151122001 = 19695534269579
BaseRepresentation
bin1100000001001110010001…
…1000110110011001010001
31201210100121121021221212121
43000103210120312121101
53213004112141401001
644034542343454241
72532522523066633
oct300234430663121
951710547257777
1013215151122001
114235572321124
121595227457381
1374b24cc2612a
1433988c428a53
1517db52d226a1
hexc04e4636651

13215151122001 has 4 divisors (see below), whose sum is σ = 13910685391600. Its totient is φ = 12519616852404.

The previous prime is 13215151121989. The next prime is 13215151122007. The reversal of 13215151122001 is 10022115151231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13215151122001 - 27 = 13215151121873 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13215151122007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 347767134771 + ... + 347767134808.

It is an arithmetic number, because the mean of its divisors is an integer number (3477671347900).

Almost surely, 213215151122001 is an apocalyptic number.

It is an amenable number.

13215151122001 is a deficient number, since it is larger than the sum of its proper divisors (695534269599).

13215151122001 is an equidigital number, since it uses as much as digits as its factorization.

13215151122001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 695534269598.

The product of its (nonzero) digits is 600, while the sum is 25.

Adding to 13215151122001 its reverse (10022115151231), we get a palindrome (23237266273232).

The spelling of 13215151122001 in words is "thirteen trillion, two hundred fifteen billion, one hundred fifty-one million, one hundred twenty-two thousand, one".

Divisors: 1 19 695534269579 13215151122001