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132155333312455 = 526431066662491
BaseRepresentation
bin11110000011000111001111…
…101100100111111111000111
3122022220221000101212222220101
4132003013033230213333013
5114310213110311444310
61145023153314544531
736556623233450635
oct3603071754477707
9568827011788811
10132155333312455
1139121842410802
12129a4709898147
13589826b2b9c9b
14248c4d0866355
1510429e449b43a
hex7831cfb27fc7

132155333312455 has 4 divisors (see below), whose sum is σ = 158586399974952. Its totient is φ = 105724266649960.

The previous prime is 132155333312441. The next prime is 132155333312461. The reversal of 132155333312455 is 554213333551231.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 132155333312455 - 215 = 132155333279687 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13215533331241 + ... + 13215533331250.

It is an arithmetic number, because the mean of its divisors is an integer number (39646599993738).

Almost surely, 2132155333312455 is an apocalyptic number.

132155333312455 is a deficient number, since it is larger than the sum of its proper divisors (26431066662497).

132155333312455 is an equidigital number, since it uses as much as digits as its factorization.

132155333312455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26431066662496.

The product of its digits is 2430000, while the sum is 46.

Adding to 132155333312455 its reverse (554213333551231), we get a palindrome (686368666863686).

The spelling of 132155333312455 in words is "one hundred thirty-two trillion, one hundred fifty-five billion, three hundred thirty-three million, three hundred twelve thousand, four hundred fifty-five".

Divisors: 1 5 26431066662491 132155333312455