Base | Representation |
---|---|
bin | 11110000011000111100000… |
… | …011100111010011110001101 |
3 | 122022220221201222211001111110 |
4 | 132003013200130322132031 |
5 | 114310214144242002131 |
6 | 1145023241235442233 |
7 | 36556633215636135 |
oct | 3603074034723615 |
9 | 568827658731443 |
10 | 132155614406541 |
11 | 39121977051970 |
12 | 129a4787a56379 |
13 | 58982b45c864b |
14 | 248c519d17ac5 |
15 | 1042a0dec3646 |
hex | 7831e073a78d |
132155614406541 has 16 divisors (see below), whose sum is σ = 203533780477248. Its totient is φ = 75382881657600.
The previous prime is 132155614406539. The next prime is 132155614406549. The reversal of 132155614406541 is 145604416551231.
It is not a de Polignac number, because 132155614406541 - 21 = 132155614406539 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132155614406549) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 117785752030 + ... + 117785753151.
It is an arithmetic number, because the mean of its divisors is an integer number (12720861279828).
Almost surely, 2132155614406541 is an apocalyptic number.
132155614406541 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
132155614406541 is a deficient number, since it is larger than the sum of its proper divisors (71378166070707).
132155614406541 is a wasteful number, since it uses less digits than its factorization.
132155614406541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 235571505212.
The product of its (nonzero) digits is 1728000, while the sum is 48.
The spelling of 132155614406541 in words is "one hundred thirty-two trillion, one hundred fifty-five billion, six hundred fourteen million, four hundred six thousand, five hundred forty-one".
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