132160250000433 has 4 divisors (see below), whose sum is σ = 176213666667248. Its totient is φ = 88106833333620.

The previous prime is 132160250000431. The next prime is 132160250000453. The reversal of 132160250000433 is 334000052061231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 132160250000433 - 2¹ = 132160250000431 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 132160250000433.

It is not an unprimeable number, because it can be changed into a prime (132160250000431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22026708333403 + ... + 22026708333408.

It is an arithmetic number, because the mean of its divisors is an integer number (44053416666812).

Almost surely, 2^{132160250000433} is an apocalyptic number.

It is an amenable number.

132160250000433 is a deficient number, since it is larger than the sum of its proper divisors (44053416666815).

132160250000433 is an equidigital number, since it uses as much as digits as its factorization.

132160250000433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44053416666814.

The product of its (nonzero) digits is 12960, while the sum is 30.

The spelling of 132160250000433 in words is "one hundred thirty-two trillion, one hundred sixty billion, two hundred fifty million, four hundred thirty-three", and thus it is an aban number.