Base | Representation |
---|---|
bin | 11000100111111000… |
… | …00100101001100111 |
3 | 1021010021122221120011 |
4 | 30103330010221213 |
5 | 204033132313204 |
6 | 10023425551051 |
7 | 645406121260 |
oct | 142374045147 |
9 | 37107587504 |
10 | 13219416679 |
11 | 567401a457 |
12 | 268b1a5487 |
13 | 1328996a61 |
14 | 8d5963967 |
15 | 525844304 |
hex | 313f04a67 |
13219416679 has 4 divisors (see below), whose sum is σ = 15107904784. Its totient is φ = 11330928576.
The previous prime is 13219416671. The next prime is 13219416701. The reversal of 13219416679 is 97661491231.
13219416679 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13219416679 - 23 = 13219416671 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13219416671) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 944244042 + ... + 944244055.
It is an arithmetic number, because the mean of its divisors is an integer number (3776976196).
Almost surely, 213219416679 is an apocalyptic number.
13219416679 is a deficient number, since it is larger than the sum of its proper divisors (1888488105).
13219416679 is an equidigital number, since it uses as much as digits as its factorization.
13219416679 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1888488104.
The product of its digits is 489888, while the sum is 49.
The spelling of 13219416679 in words is "thirteen billion, two hundred nineteen million, four hundred sixteen thousand, six hundred seventy-nine".
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