Base | Representation |
---|---|
bin | 11000100111111101… |
… | …10010110010111111 |
3 | 1021010100000012000211 |
4 | 30103332302302333 |
5 | 204033323124413 |
6 | 10023453133251 |
7 | 645415152004 |
oct | 142376626277 |
9 | 37110005024 |
10 | 13220129983 |
11 | 5674467365 |
12 | 268b48a227 |
13 | 1328b86628 |
14 | 8d5aab8ab |
15 | 52593583d |
hex | 313fb2cbf |
13220129983 has 4 divisors (see below), whose sum is σ = 13401227728. Its totient is φ = 13039032240.
The previous prime is 13220129971. The next prime is 13220130029. The reversal of 13220129983 is 38992102231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 38992102231 = 9173 ⋅4250747.
It is not a de Polignac number, because 13220129983 - 233 = 4630195391 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13220129953) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90548763 + ... + 90548908.
It is an arithmetic number, because the mean of its divisors is an integer number (3350306932).
Almost surely, 213220129983 is an apocalyptic number.
13220129983 is a deficient number, since it is larger than the sum of its proper divisors (181097745).
13220129983 is an equidigital number, since it uses as much as digits as its factorization.
13220129983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 181097744.
The product of its (nonzero) digits is 46656, while the sum is 40.
The spelling of 13220129983 in words is "thirteen billion, two hundred twenty million, one hundred twenty-nine thousand, nine hundred eighty-three".
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