Base | Representation |
---|---|
bin | 10011001111001111101… |
… | …111100110010001001111 |
3 | 11200101102021002202212011 |
4 | 103033033233212101033 |
5 | 133130014310233403 |
6 | 2451200440122051 |
7 | 164341251213325 |
oct | 23171757462117 |
9 | 4611367082764 |
10 | 1322040321103 |
11 | 46a7463286a7 |
12 | 194278766327 |
13 | 9788b3c6168 |
14 | 47db6823d15 |
15 | 245c8d6aa6d |
hex | 133cfbe644f |
1322040321103 has 4 divisors (see below), whose sum is σ = 1379520335088. Its totient is φ = 1264560307120.
The previous prime is 1322040321073. The next prime is 1322040321143. The reversal of 1322040321103 is 3011230402231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1322040321103 - 29 = 1322040320591 is a prime.
It is a super-2 number, since 2×13220403211032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1322040321143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28740006958 + ... + 28740007003.
It is an arithmetic number, because the mean of its divisors is an integer number (344880083772).
Almost surely, 21322040321103 is an apocalyptic number.
1322040321103 is a deficient number, since it is larger than the sum of its proper divisors (57480013985).
1322040321103 is an equidigital number, since it uses as much as digits as its factorization.
1322040321103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57480013984.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 1322040321103 its reverse (3011230402231), we get a palindrome (4333270723334).
The spelling of 1322040321103 in words is "one trillion, three hundred twenty-two billion, forty million, three hundred twenty-one thousand, one hundred three".
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