Base | Representation |
---|---|
bin | 11000101000000100… |
… | …11111100111110111 |
3 | 1021010101211110200020 |
4 | 30110002133213313 |
5 | 204034100200043 |
6 | 10023530020223 |
7 | 645426332055 |
oct | 142402374767 |
9 | 37111743606 |
10 | 13221100023 |
11 | 5674a6a14a |
12 | 268b877673 |
13 | 1329136011 |
14 | 8d5c811d5 |
15 | 525a77e83 |
hex | 31409f9f7 |
13221100023 has 4 divisors (see below), whose sum is σ = 17628133368. Its totient is φ = 8814066680.
The previous prime is 13221100021. The next prime is 13221100103. The reversal of 13221100023 is 32000112231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13221100023 - 21 = 13221100021 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13221099975 and 13221100011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13221100021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2203516668 + ... + 2203516673.
It is an arithmetic number, because the mean of its divisors is an integer number (4407033342).
Almost surely, 213221100023 is an apocalyptic number.
13221100023 is a deficient number, since it is larger than the sum of its proper divisors (4407033345).
13221100023 is an equidigital number, since it uses as much as digits as its factorization.
13221100023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4407033344.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 13221100023 its reverse (32000112231), we get a palindrome (45221212254).
The spelling of 13221100023 in words is "thirteen billion, two hundred twenty-one million, one hundred thousand, twenty-three".
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