Base | Representation |
---|---|
bin | 10011001111010100101… |
… | …000011010100001000010 |
3 | 11200101121222101221201202 |
4 | 103033110220122201002 |
5 | 133130201303332114 |
6 | 2451212525501202 |
7 | 164343265221041 |
oct | 23172450324102 |
9 | 4611558357652 |
10 | 1322122324034 |
11 | 46a788647716 |
12 | 1942a0111802 |
13 | 978a23a80c5 |
14 | 47dc368c558 |
15 | 245d1167cde |
hex | 133d4a1a842 |
1322122324034 has 4 divisors (see below), whose sum is σ = 1983183486054. Its totient is φ = 661061162016.
The previous prime is 1322122324009. The next prime is 1322122324097. The reversal of 1322122324034 is 4304232212231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1206695659009 + 115426665025 = 1098497^2 + 339745^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1322122323988 and 1322122324006.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 330530581007 + ... + 330530581010.
Almost surely, 21322122324034 is an apocalyptic number.
1322122324034 is a deficient number, since it is larger than the sum of its proper divisors (661061162020).
1322122324034 is an equidigital number, since it uses as much as digits as its factorization.
1322122324034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 661061162019.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 1322122324034 its reverse (4304232212231), we get a palindrome (5626354536265).
The spelling of 1322122324034 in words is "one trillion, three hundred twenty-two billion, one hundred twenty-two million, three hundred twenty-four thousand, thirty-four".
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