Base | Representation |
---|---|
bin | 10011001111010101001… |
… | …101011001101110100101 |
3 | 11200101122122122120021112 |
4 | 103033111031121232211 |
5 | 133130211244121013 |
6 | 2451213513354405 |
7 | 164343443513411 |
oct | 23172515315645 |
9 | 4611578576245 |
10 | 1322132020133 |
11 | 46a79306a521 |
12 | 1942a3408a05 |
13 | 978a43c1542 |
14 | 47dc4a93d41 |
15 | 245d1e30ba8 |
hex | 133d5359ba5 |
1322132020133 has 4 divisors (see below), whose sum is σ = 1322424337728. Its totient is φ = 1321839702540.
The previous prime is 1322132020129. The next prime is 1322132020177. The reversal of 1322132020133 is 3310202312231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1322132020133 - 22 = 1322132020129 is a prime.
It is a super-3 number, since 3×13221320201333 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1322132020099 and 1322132020108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1322132020103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 146152013 + ... + 146161058.
It is an arithmetic number, because the mean of its divisors is an integer number (330606084432).
Almost surely, 21322132020133 is an apocalyptic number.
It is an amenable number.
1322132020133 is a deficient number, since it is larger than the sum of its proper divisors (292317595).
1322132020133 is an equidigital number, since it uses as much as digits as its factorization.
1322132020133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 292317594.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 1322132020133 its reverse (3310202312231), we get a palindrome (4632334332364).
The spelling of 1322132020133 in words is "one trillion, three hundred twenty-two billion, one hundred thirty-two million, twenty thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •