Base | Representation |
---|---|
bin | 11110000011111111110001… |
… | …110011100101000101001111 |
3 | 122100010201200211000110101001 |
4 | 132003333301303211011033 |
5 | 114312211414441244210 |
6 | 1145111112533001131 |
7 | 36564202414245241 |
oct | 3603776163450517 |
9 | 570121624013331 |
10 | 132216035103055 |
11 | 39145561a504a2 |
12 | 129b442a7831a7 |
13 | 58a0bc3262587 |
14 | 249140c5dc091 |
15 | 104439862703a |
hex | 783ff1ce514f |
132216035103055 has 4 divisors (see below), whose sum is σ = 158659242123672. Its totient is φ = 105772828082440.
The previous prime is 132216035103043. The next prime is 132216035103077. The reversal of 132216035103055 is 550301530612231.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 132216035103055 - 213 = 132216035094863 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13221603510301 + ... + 13221603510310.
It is an arithmetic number, because the mean of its divisors is an integer number (39664810530918).
Almost surely, 2132216035103055 is an apocalyptic number.
132216035103055 is a deficient number, since it is larger than the sum of its proper divisors (26443207020617).
132216035103055 is an equidigital number, since it uses as much as digits as its factorization.
132216035103055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26443207020616.
The product of its (nonzero) digits is 81000, while the sum is 37.
Adding to 132216035103055 its reverse (550301530612231), we get a palindrome (682517565715286).
The spelling of 132216035103055 in words is "one hundred thirty-two trillion, two hundred sixteen billion, thirty-five million, one hundred three thousand, fifty-five".
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