13222113301 has 4 divisors (see below), whose sum is σ = 13529604352. Its totient is φ = 12914622252.

The previous prime is 13222113299. The next prime is 13222113337. The reversal of 13222113301 is 10331122231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10331122231 = 41 ⋅251978591.

It is a cyclic number.

It is not a de Polignac number, because 13222113301 - 2¹ = 13222113299 is a prime.

It is a super-2 number, since 2×13222113301² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13222113391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153745461 + ... + 153745546.

It is an arithmetic number, because the mean of its divisors is an integer number (3382401088).

Almost surely, 2^13222113301 is an apocalyptic number.

It is an amenable number.

13222113301 is a deficient number, since it is larger than the sum of its proper divisors (307491051).

13222113301 is an equidigital number, since it uses as much as digits as its factorization.

13222113301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 307491050.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13222113301 its reverse (10331122231), we get a palindrome (23553235532).

The spelling of 13222113301 in words is "thirteen billion, two hundred twenty-two million, one hundred thirteen thousand, three hundred one".