Base | Representation |
---|---|
bin | 111101100100011111… |
… | …1101000010100111011 |
3 | 110122021201101222002121 |
4 | 1323020333220110323 |
5 | 4131242103023311 |
6 | 140424101542111 |
7 | 12360364110655 |
oct | 1731077502473 |
9 | 418251358077 |
10 | 132221142331 |
11 | 5109042a253 |
12 | 21760714937 |
13 | c6120c9535 |
14 | 658448b6d5 |
15 | 368cd59b71 |
hex | 1ec8fe853b |
132221142331 has 4 divisors (see below), whose sum is σ = 132225656472. Its totient is φ = 132216628192.
The previous prime is 132221142293. The next prime is 132221142359. The reversal of 132221142331 is 133241122231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132221142331 - 27 = 132221142203 is a prime.
It is a super-2 number, since 2×1322211423312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132221142296 and 132221142305.
It is not an unprimeable number, because it can be changed into a prime (132221148331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2212846 + ... + 2271811.
It is an arithmetic number, because the mean of its divisors is an integer number (33056414118).
Almost surely, 2132221142331 is an apocalyptic number.
132221142331 is a deficient number, since it is larger than the sum of its proper divisors (4514141).
132221142331 is an equidigital number, since it uses as much as digits as its factorization.
132221142331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4514140.
The product of its digits is 1728, while the sum is 25.
Adding to 132221142331 its reverse (133241122231), we get a palindrome (265462264562).
The spelling of 132221142331 in words is "one hundred thirty-two billion, two hundred twenty-one million, one hundred forty-two thousand, three hundred thirty-one".
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