13222405433 has 4 divisors (see below), whose sum is σ = 13579767780. Its totient is φ = 12865043088.

The previous prime is 13222405423. The next prime is 13222405477. The reversal of 13222405433 is 33450422231.

It is a happy number.

13222405433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10271417104 + 2950988329 = 101348^2 + 54323^2 .

It is a cyclic number.

It is not a de Polignac number, because 13222405433 - 2¹⁰ = 13222404409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13222405396 and 13222405405.

It is not an unprimeable number, because it can be changed into a prime (13222405423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 178681118 + ... + 178681191.

It is an arithmetic number, because the mean of its divisors is an integer number (3394941945).

Almost surely, 2^13222405433 is an apocalyptic number.

It is an amenable number.

13222405433 is a deficient number, since it is larger than the sum of its proper divisors (357362347).

13222405433 is an equidigital number, since it uses as much as digits as its factorization.

13222405433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 357362346.

The product of its (nonzero) digits is 17280, while the sum is 29.

Adding to 13222405433 its reverse (33450422231), we get a palindrome (46672827664).

The spelling of 13222405433 in words is "thirteen billion, two hundred twenty-two million, four hundred five thousand, four hundred thirty-three".