Base | Representation |
---|---|
bin | 11110000100001111101011… |
… | …010000100100001010100111 |
3 | 122100012100202110021200101211 |
4 | 132010033223100210022213 |
5 | 114313001344403131101 |
6 | 1145123014434532251 |
7 | 36565345421135134 |
oct | 3604175320441247 |
9 | 570170673250354 |
10 | 132233105130151 |
11 | 39151821599503 |
12 | 129b77b3437087 |
13 | 58a26b390391c |
14 | 249218b70958b |
15 | 1044a47032c51 |
hex | 7843eb4242a7 |
132233105130151 has 4 divisors (see below), whose sum is σ = 132284101316752. Its totient is φ = 132182108943552.
The previous prime is 132233105130149. The next prime is 132233105130197. The reversal of 132233105130151 is 151031501332231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132233105130151 - 21 = 132233105130149 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132233105130131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25498089411 + ... + 25498094596.
It is an arithmetic number, because the mean of its divisors is an integer number (33071025329188).
Almost surely, 2132233105130151 is an apocalyptic number.
132233105130151 is a deficient number, since it is larger than the sum of its proper divisors (50996186601).
132233105130151 is an equidigital number, since it uses as much as digits as its factorization.
132233105130151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50996186600.
The product of its (nonzero) digits is 8100, while the sum is 31.
Adding to 132233105130151 its reverse (151031501332231), we get a palindrome (283264606462382).
The spelling of 132233105130151 in words is "one hundred thirty-two trillion, two hundred thirty-three billion, one hundred five million, one hundred thirty thousand, one hundred fifty-one".
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