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132233105130151 = 259350996184007
BaseRepresentation
bin11110000100001111101011…
…010000100100001010100111
3122100012100202110021200101211
4132010033223100210022213
5114313001344403131101
61145123014434532251
736565345421135134
oct3604175320441247
9570170673250354
10132233105130151
1139151821599503
12129b77b3437087
1358a26b390391c
14249218b70958b
151044a47032c51
hex7843eb4242a7

132233105130151 has 4 divisors (see below), whose sum is σ = 132284101316752. Its totient is φ = 132182108943552.

The previous prime is 132233105130149. The next prime is 132233105130197. The reversal of 132233105130151 is 151031501332231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132233105130151 - 21 = 132233105130149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132233105130131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25498089411 + ... + 25498094596.

It is an arithmetic number, because the mean of its divisors is an integer number (33071025329188).

Almost surely, 2132233105130151 is an apocalyptic number.

132233105130151 is a deficient number, since it is larger than the sum of its proper divisors (50996186601).

132233105130151 is an equidigital number, since it uses as much as digits as its factorization.

132233105130151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50996186600.

The product of its (nonzero) digits is 8100, while the sum is 31.

Adding to 132233105130151 its reverse (151031501332231), we get a palindrome (283264606462382).

The spelling of 132233105130151 in words is "one hundred thirty-two trillion, two hundred thirty-three billion, one hundred five million, one hundred thirty thousand, one hundred fifty-one".

Divisors: 1 2593 50996184007 132233105130151