Base | Representation |
---|---|
bin | 1100000001101101000001… |
… | …0001001011111100110011 |
3 | 1201211010220201121100222112 |
4 | 3000123100101023330303 |
5 | 3213123012244102121 |
6 | 44042425300555535 |
7 | 2533234160140643 |
oct | 300332021137463 |
9 | 51733821540875 |
10 | 13223403503411 |
11 | 42390175a9452 |
12 | 159694b0b2bab |
13 | 74bc6683385a |
14 | 33a03242c523 |
15 | 17de8757275b |
hex | c06d044bf33 |
13223403503411 has 4 divisors (see below), whose sum is σ = 13254962939400. Its totient is φ = 13191844067424.
The previous prime is 13223403503389. The next prime is 13223403503441. The reversal of 13223403503411 is 11430530432231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13223403503411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13223403503441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15779717366 + ... + 15779718203.
It is an arithmetic number, because the mean of its divisors is an integer number (3313740734850).
Almost surely, 213223403503411 is an apocalyptic number.
13223403503411 is a deficient number, since it is larger than the sum of its proper divisors (31559435989).
13223403503411 is an equidigital number, since it uses as much as digits as its factorization.
13223403503411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31559435988.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 13223403503411 its reverse (11430530432231), we get a palindrome (24653933935642).
The spelling of 13223403503411 in words is "thirteen trillion, two hundred twenty-three billion, four hundred three million, five hundred three thousand, four hundred eleven".
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