132243540534053 has 16 divisors (see below), whose sum is σ = 143394387318000. Its totient is φ = 121232702760960.

The previous prime is 132243540534037. The next prime is 132243540534143. The reversal of 132243540534053 is 350435045342231.

It can be written as a sum of positive squares in 8 ways, for example, as 43882450130689 + 88361090403364 = 6624383^2 + 9400058^2 .

It is a cyclic number.

It is not a de Polignac number, because 132243540534053 - 2⁴ = 132243540534037 is a prime.

It is a super-3 number, since 3×132243540534053³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132243540533995 and 132243540534013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132243540564053) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7032533 + ... + 17718453.

It is an arithmetic number, because the mean of its divisors is an integer number (8962149207375).

Almost surely, 2^{132243540534053} is an apocalyptic number.

132243540534053 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

132243540534053 is a deficient number, since it is larger than the sum of its proper divisors (11150846783947).

132243540534053 is a wasteful number, since it uses less digits than its factorization.

132243540534053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10692472.

The product of its (nonzero) digits is 2592000, while the sum is 44.

Adding to 132243540534053 its reverse (350435045342231), we get a palindrome (482678585876284).

The spelling of 132243540534053 in words is "one hundred thirty-two trillion, two hundred forty-three billion, five hundred forty million, five hundred thirty-four thousand, fifty-three".