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132251504011 = 1120521585881
BaseRepresentation
bin111101100101011001…
…1011100110110001011
3110122100211112111111021
41323022303130312023
54131322341112021
6140431104413311
712361213143664
oct1731263346613
9418324474437
10132251504011
11510a6587450
122176a917237
13c61849a023
14658851236b
153690855c41
hex1ecacdcd8b

132251504011 has 8 divisors (see below), whose sum is σ = 144281644848. Its totient is φ = 120222576000.

The previous prime is 132251503963. The next prime is 132251504017. The reversal of 132251504011 is 110405152231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132251504011 - 29 = 132251503499 is a prime.

It is not an unprimeable number, because it can be changed into a prime (132251504017) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 67210 + ... + 518671.

It is an arithmetic number, because the mean of its divisors is an integer number (18035205606).

Almost surely, 2132251504011 is an apocalyptic number.

132251504011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

132251504011 is a deficient number, since it is larger than the sum of its proper divisors (12030140837).

132251504011 is a wasteful number, since it uses less digits than its factorization.

132251504011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 606413.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 132251504011 its reverse (110405152231), we get a palindrome (242656656242).

The spelling of 132251504011 in words is "one hundred thirty-two billion, two hundred fifty-one million, five hundred four thousand, eleven".

Divisors: 1 11 20521 225731 585881 6444691 12022864001 132251504011