Base | Representation |
---|---|
bin | 111101100101011001… |
… | …1011100110110001011 |
3 | 110122100211112111111021 |
4 | 1323022303130312023 |
5 | 4131322341112021 |
6 | 140431104413311 |
7 | 12361213143664 |
oct | 1731263346613 |
9 | 418324474437 |
10 | 132251504011 |
11 | 510a6587450 |
12 | 2176a917237 |
13 | c61849a023 |
14 | 658851236b |
15 | 3690855c41 |
hex | 1ecacdcd8b |
132251504011 has 8 divisors (see below), whose sum is σ = 144281644848. Its totient is φ = 120222576000.
The previous prime is 132251503963. The next prime is 132251504017. The reversal of 132251504011 is 110405152231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132251504011 - 29 = 132251503499 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132251504017) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 67210 + ... + 518671.
It is an arithmetic number, because the mean of its divisors is an integer number (18035205606).
Almost surely, 2132251504011 is an apocalyptic number.
132251504011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
132251504011 is a deficient number, since it is larger than the sum of its proper divisors (12030140837).
132251504011 is a wasteful number, since it uses less digits than its factorization.
132251504011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 606413.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 132251504011 its reverse (110405152231), we get a palindrome (242656656242).
The spelling of 132251504011 in words is "one hundred thirty-two billion, two hundred fifty-one million, five hundred four thousand, eleven".
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