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132256516212031 = 373574500438163
BaseRepresentation
bin11110000100100101011110…
…101010110000010100111111
3122100021121012000100212022111
4132010211132222300110333
5114313342321122241111
61145141445455354451
736600134523063151
oct3604453652602477
9570247160325274
10132256516212031
1139160745532862
1212a00247822a27
1358a4974bb44b3
14249336ca44ad1
151045467494a21
hex78495eab053f

132256516212031 has 4 divisors (see below), whose sum is σ = 135831016650232. Its totient is φ = 128682015773832.

The previous prime is 132256516212017. The next prime is 132256516212071. The reversal of 132256516212031 is 130212615652231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132256516212031 - 237 = 132119077258559 is a prime.

It is a super-2 number, since 2×1322565162120312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132256516212001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1787250219045 + ... + 1787250219118.

It is an arithmetic number, because the mean of its divisors is an integer number (33957754162558).

Almost surely, 2132256516212031 is an apocalyptic number.

132256516212031 is a deficient number, since it is larger than the sum of its proper divisors (3574500438201).

132256516212031 is an equidigital number, since it uses as much as digits as its factorization.

132256516212031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3574500438200.

The product of its (nonzero) digits is 129600, while the sum is 40.

The spelling of 132256516212031 in words is "one hundred thirty-two trillion, two hundred fifty-six billion, five hundred sixteen million, two hundred twelve thousand, thirty-one".

Divisors: 1 37 3574500438163 132256516212031