Base | Representation |
---|---|
bin | 11110000100101100110000… |
… | …001100110011011100101001 |
3 | 122100022100100022212210102020 |
4 | 132010230300030303130221 |
5 | 114314004320043340040 |
6 | 1145145220502055053 |
7 | 36600532211564616 |
oct | 3604546014633451 |
9 | 570270308783366 |
10 | 132264326543145 |
11 | 39163a93234165 |
12 | 12a0186741a489 |
13 | 58a561b0497b4 |
14 | 24938b005950d |
15 | 1045772ec6cd0 |
hex | 784b30333729 |
132264326543145 has 32 divisors (see below), whose sum is σ = 212405211446400. Its totient is φ = 70280347282944.
The previous prime is 132264326543143. The next prime is 132264326543171. The reversal of 132264326543145 is 541345623462231.
It is not a de Polignac number, because 132264326543145 - 21 = 132264326543143 is a prime.
It is a super-3 number, since 3×1322643265431453 (a number of 43 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (132264326543143) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11302101 + ... + 19805709.
It is an arithmetic number, because the mean of its divisors is an integer number (6637662857700).
Almost surely, 2132264326543145 is an apocalyptic number.
132264326543145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
132264326543145 is a deficient number, since it is larger than the sum of its proper divisors (80140884903255).
132264326543145 is a wasteful number, since it uses less digits than its factorization.
132264326543145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8507449.
The product of its digits is 12441600, while the sum is 51.
The spelling of 132264326543145 in words is "one hundred thirty-two trillion, two hundred sixty-four billion, three hundred twenty-six million, five hundred forty-three thousand, one hundred forty-five".
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