13230000110114 has 4 divisors (see below), whose sum is σ = 19845000165174. Its totient is φ = 6615000055056.

The previous prime is 13230000110087. The next prime is 13230000110123. The reversal of 13230000110114 is 41101100003231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11154484467889 + 2075515642225 = 3339833^2 + 1440665^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13230000110092 and 13230000110101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3307500027527 + ... + 3307500027530.

Almost surely, 2^{13230000110114} is an apocalyptic number.

13230000110114 is a deficient number, since it is larger than the sum of its proper divisors (6615000055060).

13230000110114 is an equidigital number, since it uses as much as digits as its factorization.

13230000110114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6615000055059.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13230000110114 its reverse (41101100003231), we get a palindrome (54331100113345).

The spelling of 13230000110114 in words is "thirteen trillion, two hundred thirty billion, one hundred ten thousand, one hundred fourteen".