13230100011311 has 4 divisors (see below), whose sum is σ = 13389498806712. Its totient is φ = 13070701215912.

The previous prime is 13230100011269. The next prime is 13230100011353. The reversal of 13230100011311 is 11311000103231.

13230100011311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13230100011269) and next prime (13230100011353).

It is a cyclic number.

It is not a de Polignac number, because 13230100011311 - 2¹⁴ = 13230099994927 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13230100011311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13230100011361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79699397576 + ... + 79699397741.

It is an arithmetic number, because the mean of its divisors is an integer number (3347374701678).

Almost surely, 2^{13230100011311} is an apocalyptic number.

13230100011311 is a deficient number, since it is larger than the sum of its proper divisors (159398795401).

13230100011311 is an equidigital number, since it uses as much as digits as its factorization.

13230100011311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 159398795400.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13230100011311 its reverse (11311000103231), we get a palindrome (24541100114542).

The spelling of 13230100011311 in words is "thirteen trillion, two hundred thirty billion, one hundred million, eleven thousand, three hundred eleven".